Theorem 2.3 (Continuous functions). Let C [a, b] be the vector space of continu-
ous functions on [a, b]. Then C [a, b] ⊂ D [a, b]. In other words, every continuous
function is integrable.
This is a major achievement. Since continuous functions can be manipulated
with a very nice kind of arithmetic, we now realize just how big D [a, b] is.
Consequently, arbitrary compositions of continuous functions are still integrable.
Thus a function like f(x) = e
−x
2
is integrable. This is important: the theorem
is a statement about existence, it does not provide us with a way to calculate
integrals. This is the content of the two following theorems. These are the
cornerstones of calculus.
Theorem 2.4 (Fundamental Theorem of Calculus, Part. I). Let f be a contin-
uous function defined on [a, b]. Let F be the function defined, for all x in [a, b],
by
Z
x
a
f(t) dt. Then F is uniformly continuous on [a, b], differentiable on (a, b)
and F
0
(x) = f(x) for all x ∈ [a, b].
Theorem 2.5 (Fundamental Theorem of Calculus, Part. II). Let f be a func-
tion integrable on [a, b] and let F be an antiderivative of f on [a, b]. Then,
Z
b
a
f(x) dx = F (b) − F (a).
It is this second part that is widely used in applications. We now understand
why this method fails for f (x) = e
−x
2
. One can show that this function has
no antiderivative in terms of elementary functions, hence why we use numerical
methods to approximate it.
We will end this chapter with a criterion for integrability that will tell us exactly
which functions are Darboux-integrable. To do that, we first need a definition.
Definition 2.9 (Sets of measure zero). Let N be a subset of the real numbers.
We say that N has measure zero if it can be covered by a countable union
of intervals whose lengths are arbitrarily small. More formally, for every > 0,
there exists a collection {U
n
}
∞
n=1
such that
N ⊂ ∪
∞
n=1
and
∞
X
n=1
|U
n
| <
.
This leads us to Lebesgue’s wonderful classification theorem.
Theorem 2.6. Suppose f is a bounded function defined on [a, b]. Then, f is
integrable if and only if it is continuous almost everywhere, that is, the set
of discontinuities of f is a set of measure zero. Thus, any function with at most
a countably infinite number of discontinuities is integrable.
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